⚡ XP: 0
06:00

👁️ TA Brief — This Slide

Loading…

🎯 Random Pupil Picker

No pupils added yet

Tap a grade chip beside each name to set tier (U/1/2/3/4/5). Easier=U/1, Match=2, Stretch=3–5.

🏆

Lesson Complete!

You caught up on the calculations and locked in your electricity skills. Brilliant focus — onto Waves next. ⚡🌊

0XP earned
11slides done

Physics — Catch-Up & Consolidation Lesson

Electricity Calculations & Bridge to Waves

🔢🌊

Re-building L2c & L4 calculations  |  Bridge to Waves

Missed a lesson? You're in exactly the right place. Lots of us were away for the calculation lessons, so today we re-build them together from scratch — slowly, step by step. This isn't a test. It's a catch-up.
L1 — Recall circuit symbols, series & parallel (quick recap — you didn't miss this one)
L2c — Use V = I × R and rearrange it (find V, I or R)
L4 — Explain electron flow & solve series circuit calculations

🏆 Today's Success Criteria

Foundation: I can use V = I × R and add resistances in series.

Middle: I can rearrange V = IR and find the current in a series circuit.

Higher: I can solve a full series problem and explain voltage sharing.

🖨️ Pupil Packs

⏱️ 40-Minute Pacing (calc-focused)

Core: Arrival → Starter → I Do VIR → We Do Carousel → I Do Series → We Do Series Solver → Independent → Exit

🟠 FLEX (use if time/confidence allows): Common Mistakes + Symbol Speed Match. You didn't miss L1 symbols, so they're optional today.

⏱️ 4 min
Arrival Task

Arrival – How Much Do You Remember?

No notes. Answer from memory. One from L1, one from L2c, one from L4. If you were away — just have a go. We re-build it all together shortly.

1. 🟢 (L1)

Draw the circuit symbol for a cell and a lamp.

Cell: long line + short line. Lamp: circle with a cross.

2. 🟢 (L2c)

Write the formula linking voltage, current and resistance.

V = I × R

3. 🟢 (L4)

What particles carry current in a metal wire?

Electrons (negatively charged).

4. Bridge 🌊

Name two types of wave you know about.

Any from: water waves, sound waves, light waves, radio waves, etc.

⏱️ 3 min
Starter

Starter: Electricity Brain Dump 🧠

Instructions: In 3 minutes, write down everything you can remember about electricity. Facts, formulas, units, rules — anything! Blank under a topic? That's fine — it just shows what we'll re-build today.

📝 Brain Dump — Write everything!

Challenge yourself: can you get 10+ facts?

🟢 5+ facts = Good  |  🟠 10+ facts = Great  |  🔵 15+ facts = Expert!

💡 Topics to jog your memory:

L1: Circuit symbols, series vs parallel, ammeter/voltmeter

L2c: V = I × R, units, water analogy, VIR triangle

L4: Electron flow, conventional current, series R rules, voltage sharing

💡 Did You Know?

Revisiting content 24 hours later can boost long-term memory by up to 80%. Catching up today fires the pathways back up — even if you missed the lesson first time.

🌟 After 3 minutes: Swap books with a partner. Read their list. Add anything they missed in a different colour. Discuss!
⏱️ 4 min
I Do

I Do: The VIR Triangle — From Scratch (L2c)

Missed the Ohm's Law lesson? Watch this carefully. Every calculation uses the same 3 steps. I'll reveal them one at a time.
V = I × R
V I × R ?
👆 Tap a button — I'll cover that letter and show the formula.
PUMP (V) narrow = R flow of water = current (I)

Bigger pump (more V) → faster flow (more I). Narrower pipe (more R) → slower flow (less I). That's V = I × R!

Every calculation, every time: ① write the Formula → ② Substitute the numbers → ③ Answer + Unit (V, A or Ω). Even the formula alone can earn a mark.
↗ Open on YouTube

① Find R — cover R

Step 1 – Formula: R = V ÷ I

Step 2 – Substitute: R = 10 ÷ 2

Step 3 – Answer: R = 5 Ω

② Find I — cover I

Step 1: I = V ÷ R

Step 2: I = 12 ÷ 4

Step 3: I = 3 A

③ Find V — cover V

Step 1: V = I × R

Step 2: V = 0.5 × 12

Step 3: V = 6 V

⚠️ The #1 mistake: "I = V × R"
Truth: To find I or R you DIVIDE. You only multiply when you want V. The triangle never lies — cover the unknown.
⏱️ 5 min
We Do

We Do: VIR Problem Carousel 🎠 (L2c)

Your turn. The first one is done for you — copy the routine. Calculate the missing value, type it, check!

✅ Worked example — Lamp

V = 6 V, R = 3 Ω, find I. → Cover I → I = V ÷ R = 6 ÷ 3 = 2 A

👥 Think-Pair-Share: try it → discuss with your partner → agree the answer.
🔦

Torch

V = 3 V, R = 6 Ω

I = ?

A
Cover I → I = V ÷ R. Put in 3 ÷ 6.
📱

Phone Charger

I = 2 A, R = 2.5 Ω

V = ?

V
Cover V → V = I × R. Put in 2 × 2.5.
💡

LED Bulb

V = 12 V, I = 0.5 A

R = ?

Ω
Cover R → R = V ÷ I. Dividing by 0.5 doubles the number.
🧹

Vacuum

V = 230 V, R = 23 Ω

I = ?

A
Cover I → I = V ÷ R = 230 ÷ 23.
🎮

Game Controller

I = 0.1 A, R = 30 Ω

V = ?

V
Cover V → V = I × R = 0.1 × 30.
🔌

Kettle

V = 230 V, I = 10 A

R = ?

Ω
Cover R → R = V ÷ I = 230 ÷ 10.
Solved:
0/6
⏱️ 4 min
I Do

I Do: Series Circuit Calculations — From Scratch (L4)

Missed the series lesson? Watch the 4-step method. In series: add the resistances, the current is the same everywhere, and the voltages add up to the supply.

✏️ Problem

An 18 V battery is connected to a 6 Ω and a 12 Ω resistor in series. Find Rtotal, the current, and the voltage across each.

Step 1 — Add the resistances:
Rtotal = R₁ + R₂ = 6 + 12 = 18 Ω

Step 2 — Find the current:
I = V ÷ Rtotal = 18 ÷ 18 = 1 A

Step 3 — Voltage across each:
V₁ = I × R₁ = 1 × 6 = 6 V
V₂ = I × R₂ = 1 × 12 = 12 V

Step 4 — Check: V₁ + V₂ = 6 + 12 = 18 V = supply ✅

Series Circuit — watch the charge flow

Battery 6 Ω 12 Ω

The dots keep the same spacing & speed all the way round — the current is the same everywhere.

Supply:18 V
V₁ 6 V
V₂ 12 V

Current now: 1 A — and the 12 Ω always grabs double the voltage of the 6 Ω (voltage shares by resistance).

Rtotal = R₁ + R₂
The routine, every series question: ① Add R → ② I = V ÷ Rtotal → ③ V = I × R for each → ④ Check the voltages add up.
↗ Open on YouTube
⚠️ Two classic slips: "R total = 6 × 12" — no, you ADD in series. And "current shrinks after a resistor" — no, current is the SAME everywhere; it's the voltage that's shared.
🌟 Notice: the 12 Ω gets double the voltage of the 6 Ω — voltage is shared in proportion to resistance.
⏱️ 5 min
We Do

We Do: Series Circuit Step Solver 🧮 (L4)

Your turn — one step at a time. A 20 V battery connects to 5 Ω and 15 Ω in series. Use a hint whenever you're stuck — that's what they're for.
👥 Think-Pair-Share: try each step → check with your partner → agree.

Step 1: Add the resistances (Rtotal)

Rtotal = 5 + 15 = Ω

Series resistances ADD together: 5 + 15.

Step 2: Find the current (I)

I = V ÷ Rtotal = 20 ÷ 20 = A

Divide the battery voltage by Rtotal: 20 ÷ 20.

Step 3: Voltage across the 5 Ω

V₁ = I × R₁ = 1 × 5 = V

Multiply the current by this resistor: 1 × 5.

Step 4: Voltage across the 15 Ω

V₂ = I × R₂ = 1 × 15 = V

Multiply the current by this resistor: 1 × 15.

Step 5: CHECK — do they add up?

V₁ + V₂ = 5 + 15 = V = supply?

Add your two voltages — they should equal the 20 V supply.
Steps correct: 0 / 5
🌟 Finished? Try it again with a 24 V battery, 4 Ω + 8 Ω. (R=12, I=2 A, V₁=8 V, V₂=16 V.)
⏱️ 3 min · FLEX
I Do · FLEX

Top 4 Mistakes to Avoid

Optional recap. Everyone makes these — spotting them is how you stop losing easy marks.

❌ Mistake 1: Multiplying to find I

"I = V × R = 12 × 4 = 48"

✅ Fix: I = V ÷ R = 12 ÷ 4 = 3 A

❌ Mistake 2: Multiplying series R

"R total = 3 × 6 = 18 Ω"

✅ Fix: R total = 3 + 6 = 9 Ω (ADD in series)

❌ Mistake 3: Forgetting the unit

"V = 3 × 4 = 12" (no unit!)

✅ Fix: V = 3 × 4 = 12 V (always write V, A or Ω)

❌ Mistake 4: Current changes in series

"The current is smaller after the resistor"

✅ Fix: In series, current is the SAME everywhere. Voltage is what's shared.

💡 Rule of thumb: finding I or R → you DIVIDE. Finding V → you MULTIPLY. The triangle never lies!
⏱️ 5 min · FLEX
We Do · FLEX

Symbol Speed Match ⚡ (L1)

Optional L1 revision. Click a component, then click its matching description. Match all 6!

Component (click first)

Cell
Ammeter
Voltmeter
Resistor
Switch (open)
Lamp

How it's connected / what it does

Measures voltage. Connected in parallel.
Converts electrical energy to light + heat.
Provides voltage (push). Long + short line.
Breaks the circuit. Gap in the wire.
Measures current. Connected in series.
Opposes flow of current. Rectangle symbol.
Matched: 0 / 6
⏱️ 6 min
Independent Work

Independent Work

Complete your printed pack. The calculations you've just re-built are the focus. Use your scaffolding sheet whenever you need it.

📝 Pack Contains:

A: Multiple Choice — mixed L1/L2c/L4 (4 Qs)

B: Short Answer — symbols, definitions, V=IR

C: Long Answer — scaffolded series calculation

D: Exam-Style — full series circuit problem

Need help? The Scaffolding Sheet has every formula, the series rules, and the VIR triangle.
📝 Exam Command Words:
State = write a fact, no explanation.
Calculate = formula → substitute → answer + unit.
Explain = what happens AND why (use "because").
Describe = what happens, step by step.

🏆 Success Criteria

Foundation (U–1): I can use V = I × R and add resistances in series.

Middle (1–2): I can rearrange V = IR and find the current in a series circuit.

Higher (3–5): I can solve a full series problem, find a missing R, and explain voltage sharing.

✅ Tick as you go — Success checklist

I can use V = I × R and rearrange it
I can add resistances in series (R total)
I can find the current in a series circuit
I can explain what carries current in metals
⏱️ 3 min
Exit Ticket

Exit Ticket — L1, L2c & L4 Cumulative

6 questions — 2 from each lesson. No notes.
🟢 I'm confident — I could teach this
🟡 Getting there — need more practice
🔴 I'm stuck — I need help
L1

1. Name the quantity measured with an ammeter.

Current (in amps).

L1

2. In series, is the current the same or different everywhere?

The same everywhere.

L2c

3. I = 3 A, R = 4 Ω. Calculate V.

V = 3 × 4 = 12 V

L2c

4. What unit is resistance measured in?

Ohms (Ω)

L4

5. What carries current in a metal wire?

Negatively charged electrons.

L4

6. 4 Ω + 6 Ω in series. R total = ?

R = 4 + 6 = 10 Ω

🌊 Coming next lesson: a brand-new topic — WAVES! Amplitude, wavelength, frequency, and how waves transfer energy without transferring matter. Get excited!
Slide 1/11